MySQL中关于本月、本年、本季度时间的查询方法

2019-01-02 15:51 阅读 505 次 评论 1 条

MySQL中关于本月、本年、本季度时间的查询方法,如下:

-- 今天
select * from ticket_order_detail where to_days(use_time) = to_days(now());

-- 7天
SELECT *FROM ticket_order_detail where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date( use_time)

-- 近30天
SELECT *FROM ticket_order_detail where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date( use_time)

-- 本月
SELECT *FROM ticket_order_detail WHERE DATE_FORMAT( use_time, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )

-- 上一月
SELECT *FROM ticket_order_detail WHERE PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( use_time, '%Y%m' ) ) =1

#查询本季度数据
select * from `ticket_order_detail` where QUARTER(use_time)=QUARTER(now());

#查询上季度数据
select * from `ticket_order_detail` where QUARTER(use_time)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));

#查询本年数据
select * from `ticket_order_detail` where YEAR(use_time)=YEAR(NOW());

#查询上年数据
select * from `ticket_order_detail` where year(use_time)=year(date_sub(now(),interval 1 year));

-- 查询当前这周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,’%Y-%m-%d’)) = YEARWEEK(now());

-- 查询上周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,’%Y-%m-%d’)) = YEARWEEK(now())-1;

-- 查询当前月份的数据
select name,submittime from enterprise where date_format(submittime,’%Y-%m’)=date_format(now(),’%Y-%m’)

-- 查询距离当前现在6个月的数据
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();

-- 查询上个月的数据
select name,submittime from enterprise where date_format(submittime,’%Y-%m’)=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),’%Y-%m’)

select*from`user`where DATE_FORMAT(pudate,‘%Y%m‘)=DATE_FORMAT(CURDATE(),‘%Y%m‘) ;

select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,’%y-%m-%d’)) = WEEKOFYEAR(now())

select * from user where MONTH(FROM_UNIXTIME(pudate,‘%y-%m-%d‘))=MONTH(now())

select * from user where YEAR(FROM_UNIXTIME(pudate,‘%y-%m-%d‘))=YEAR(now())
and MONTH(FROM_UNIXTIME(pudate,‘%y-%m-%d‘))=MONTH(now())

select * from user
-- where pudate between上月最后一天
-- and下月第一天
where date(regdate) = curdate();

select * from test where year(regdate)=year(now()) and month(regdate)=month(now()) and             day(regdate)=day(now())

SELECT date( c_instime ) ,curdate( )  FROM `t_score`  WHERE 1  LIMIT 0 , 30

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  1. 免费节点
    免费节点 【农民】 @回复

    写的太好了,为你点赞!